Q. $H_{2}O_{2}$ is manufactured these days

A) By the action of $H_{2}O_{2}\ on\ BaO_{2}$
B) By the action of $H_{2}SO_{4}\ on\ Na_{2}O_{2}$
C) By electrolysis of 50% $H_{2}SO_{4}$
D) By burning hydrogen in excess of oxygen
Explanation

(c)
Electrolysis of 50% sulphuric acid is the commercial method for the preparation of hydrogen peroxide.
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ H_{2}SO_{4} = H^{+} + \ HSO_{4}^{-}$
At anode
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2HSO_{4}^{-}\ \rightarrow H_{2}S_{2}O_{8} + \ 2e^{-}$
$\ H_{2}S_{2}O_{8} + \ 2H_{2}O\ \rightarrow 2H_{2}SO_{4} + \ H_{2}O_{2}$
At cathode
$\ \ \ \ \ \ \ \ \ \ \ 2H + 2e^{-}\ \rightarrow H_{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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