Q. The strength in volumes of a solution containing $30.36\ g/L\ of\ H_{2}O_{2}is$
A) 10 V
B) 5 V
C) 20 V
D) None of these
Explanation
(a)
$Eq.wt.of\ H_{2}O_{2} = 17$
$N = \frac{30.36}{17} = 1.78\ N$
$Volume\ strength = 5.6 \times normality\$
$= 5.6 \times 1.78 = 10\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.