(c)
$\begin{matrix}
\ \ \ \ \ \ \ \ + 7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
2K\ MnO_{4} + 3H_{2}SO_{4} + \ 5H_{2}O_{2}\
\end{matrix}$
$\ \ \ \ \ \ \ \ + 2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0\ \ \ \$
$\rightarrow 2MnSO_{4} + \ 8H_{2}O + 5O_{2}$
In this reaction hydrogen peroxide acts as a reducing agent and it reduces $KMnO_{4}\ to\ \ Mn^{2 +}$ ions.