Explanation

(d)
$Na_{2}SO_{3}$ is oxidised by $H_{2}O_{2}\ to\ Na_{2}SO_{4}$
PbS is oxidised by $H_{2}O_{2}$ to $PbSO_{4}$
KI is oxidised by $H_{2}O_{2}\ to\ I_{2}$
$O_{3}$ cannot be oxidised by $H_{2}O_{2}$ but it is reduced to $O_{2}$ by $H_{2}O_{2}$
$\ \ \ \ \ \ \ \ \ \ H_{2}O_{2} + \ O_{3} \rightarrow H_{2}O + 2O_{2}$