Q. Sodium peroxide which is a yellow solid, when exposed to air becomes white due to the formation of
A) $H_{2}O_{2}$
B) $Na_{2}O\$
C) $Na_{2}O\ and\ O_{3}$
D) $NaOH\ and\ Na_{2}CO_{3}$
Explanation
(d)
Sodium peroxide reacts with moisture and $CO_{2}$ of air (when exposed to air) and becomes white due to the formation of NaOH and $Na_{2}CO_{3}.$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2Na_{2}O_{2} + 2H_{2}O\ \rightarrow 4NaOH + O_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2NaOH + CO_{2}\ \rightarrow Na_{2}CO_{3} + H_{2}O$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.