Q. Which of the following reaction does not liberate gaseous product?
A) $AlCl_{3} + \ NaOH\ \ \rightarrow$
B) $NaOH + P(white) + H_{2}O\ \rightarrow$
C) $Al + \ NaOH\ \ \overset{\ \ \ \ \ \mathrm{\Delta}\ \ \ \ \ \ }{\rightarrow}$
D) $Zn + \ NaOH\ \ \overset{\ \ \ \ \ \mathrm{\Delta}\ \ \ \ \ \ }{\rightarrow}$
Explanation
(a)
When $AlCl_{3}$ reacts with NaOH, it forms sodium meta aluminate $\left( NaAlO_{2} \right).$ This reaction does not give gaseous product.
$AlCl_{3} + 4NaOH\ \rightarrow NaAlO_{2} + 2H_{2}O + 3NaCl$
sodium meta aluminate (soluble)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.