Q. A metal $M$ forms water soluble $MSO_{4}$ and inert $MO.MO$ in aqueous solution forms insoluble $M(OH)_{2}$ soluble in NaOH. Metal $M$ is
A) Be
B) Mg
C) Ca
D) Si
Explanation
(a)
Metal $M$ is Be.
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ BeO + H_{2}O\ \longrightarrow Be(OH)_{2}.$
$Be(OH)_{2} + 2NaOH\ \longrightarrow Na_{2}BeO_{2} + 2H_{2}O$
Soluble
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.