Q. Aluminium chloride exists as $dimer$, $Al_{2}Cl_{6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
A) $\left\lbrack Al(OH)_{6} \right\rbrack^{3 -} + \ 3HCl$
B) $Al_{2}O_{3} + \ 6HCl$
C) ${Al}^{3 +} + \ 3Cl^{-}$
D) $\left\lbrack Al\left( H_{2}O \right)_{6} \right\rbrack^{3 +} + \ 3Cl^{-}$
Explanation
The correct answer is Option D: $\left\lbrack Al\left( H_{2}O \right)_{6} \right\rbrack^{3 +} + \ 3Cl^{-}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.