Q. $(Me)_{2}SiCl_{2}$ on hydrolysis will produce

A) $(Me)_{2}Si(OH)_{2}$
B) $(Me)_{2}Si = O\$
C) $\left\lbrack - O - (Me)_{2}Si - O - \right\rbrack_{n}$
D) $Me_{2}SiCl(OH)$
Explanation

(c)
$Me_{2}SiCl_{2}$ on hydrolysis will produce $Me_{2}Si(OH)_{2}$ as follows
[image:11_image10.emf]
$MeSi(OH)_{2}$ is unstable compound and it loses water molecule to give $Me_{2}SiO$. But silicon atom because of its very large size in comparison to oxygen, is unable to form $\pi$-bond. Thus, the product of hydrolysis is polymeric in nature.
[image:11_image11.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.