Q. On controlled hydrolysis and condensation, $R_{3}SiCl$ yields
A) $R_{3}Si - O - SiR_{3}$
B) $\left( - R_{3}Si - O - SiR_{3} - \right)_{n}$
C) $R_{3}SiOH$
D) $R$ $R$
$|$ $|$
$- Si - O - Si$
$|$ $|$
$O$ $O$
$|$ $|$
$- Si - O - Si -$
$|$ $|$
Explanation
(a)
$R_{3}SiCl$ on hydrolysis can only form a dimer.
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ R_{3}SiCl\overset{{\ \ \ H}_{2}O\ \ \ \ }{\rightarrow}R_{3}SiOH$
$R_{3}SiOH + R_{3}SiOH\overset{\rightarrow}{\ \ - H_{2}O\ \ \ }R_{3}Si - O - SiR_{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.