Q. $\left( CH_{3} \right)_{2}SiCl_{2}$ undergoes hydrolysis but $\left( CH_{3} \right)_{2}CCl_{2}$ does not why?
A) Low lying $d$-orbitals present in Si but not in C
B) Only 3$p$ orbital is involved in C
C) Silicon is more acidic
D) $Si - Cl$ bond is more polar than $C - Cl$ bond
Explanation
(a)
$\left( CH_{3} \right)_{2}SiCl_{2}$ undergoes hydrolysis but $\left( CH_{3} \right)_{2}CCl_{2}$ does not because in Si, low lying $d$-orbital is present but in C, it does not present.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.