(a)
In bauxite ore, only $Al_{2}O_{3}$ reacts with conc. $NaOH$ and forms sodium meta aluminate.
This further dissolves in water.
$Al_{2}O_{3} + 2H_{2}O + 2NaOH\underset{35\ bar}{\overset{\ \ \ \ 500\ K\ \ \ }{\rightarrow}}2NaAlO_{2} + 3H_{2}O$
$NaAlO_{2} + 2H_{2}O \rightarrow NaAl(OH)_{4}$