Q. Identify $B$ in the following reaction, $H_{4}SiO_{4}\underset{- H_{2}O}{\overset{\ \ \ 1000℃\ \ \ }{\rightarrow}}A\underset{\mathrm{\Delta}}{\overset{\ \ \ \ Carbon\ \ \ }{\rightarrow}}B + CO$

A) Corundum
B) Quartz
C) Silica
D) Carborundum
Explanation

(d)
Orthosilicic acid $\left( H_{4}SiO_{4} \right)$, on heating at high temperature, loses two water molecules and gives silica $(SiO_{2})$ which on reduction with carbon gives carborundum $(SiC)$ and $CO$.
$H_{4}SiO_{4}\underset{- 2H_{2}O}{\overset{\ \ 1000℃\ \ }{\rightarrow}}SiO_{2}\underset{\mathrm{\Delta}}{\overset{\ \ \ C\ \ \ }{\rightarrow}}SiC + CO$
carborundum

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.