Q. When $C_{2}H_{5},\ CH_{4}\ and\ C_{2}H_{4}$ passes through a test tube which have ammoniacal $Cu_{2}Cl_{2}$, find out which gas comes out unaffected from test tube?
A) $C_{2}H_{2}\ and\ CH_{4}$
B) $C_{2}H_{2}\ and\ C_{2}H_{4}$
C) $C_{2}H_{4}\ and\ CH_{4}$
D) $C_{2}H_{2}$
Explanation
(c)
Copper and silver alkylides are obtained by passing to alkynes in the ammoniacal solution of cuprous chloride and silver nitrate respectively. These reactions are used for detecting the presence of acetylenic hydrogen atom.
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So, alkanes and alkenes remain unaffected.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.