Q. $CH_{3}COCH_{3}$ can be converted to $CH_{3}CH_{2}CH_{3}$ by the action of
A) $HNO_{3}$
B) $HIO_{3}$
C) $H_{3}PO_{3}$
D) $HI$
Explanation
(d)
$HIO_{3}$and$HNO_{3}$ both are oxidizing agent. HI is reducing agent which can reduce $CH_{3}COCH_{3}$ to propane,
$CH_{3} - COCH_{3} + 4HI \rightarrow CH_{3}CH_{2}CH_{3} + H_{2}O + 2I_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.