Q. When acetylene is passed through red hot iron tube, compound $X$ is formed. Which one of the following reactions will yield $X$ as the major product?
A) $C_{6}H_{5}OH + Zn\overset{Distillation}{\rightarrow}$
B) $C_{6}H_{5}SO_{3}H + NaHCO_{3} \rightarrow$
C) $C_{6}H_{12} + 3H_{2}\overset{Ni\ \ \ \ }{\rightarrow}$
D) $C_{6}H_{5}Cl + H_{2}O\overset{\mathrm{\Delta}}{\rightarrow}$
Explanation
(a)
When acetylene is passed through red hot iron tube, benzene is formed as
$3C_{2}H_{2}\overset{Red\ hot\ tube}{\rightarrow}C_{6}H_{6}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (X)$
Reaction (a) also gives $C_{6}H_{6}\ (or\ X)$ as
$C_{6}H_{5}OH + Zn\overset{Distillation}{\rightarrow}C_{6}H_{6} + ZnO$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.