(a)
$Cl_{3} - C - CH = {CH}_{2}\underset{anti - Markownikoff\ rule}{\overset{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ HCl\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}\ Cl_{3} - C - CH_{2} - CH_{2}Cl$
($\because CCl_{3}$is highly electron attracting group)