Q. In the reaction, $C_{6}H_{5}CH_{3}\overset{Oxidation}{\rightarrow}A{\overset{NaOH}{\rightarrow}B{\overset{Soda\ lime}{\rightarrow}C}}$ The product $C$ is
A) $C_{6}H_{5}OH$
B) $C_{6}H_{6}$
C) $C_{6}H_{5}COONa$
D) $C_{6}H_{5}ONa$
Explanation
(b)
$C_{6}H_{5}CH_{3}\overset{Oxidation\ \ }{\rightarrow}C_{6}H_{5}.COOH\overset{NaOH\ \ }{\rightarrow}$
$(A)$
$C_{6}H_{5}COONa\overset{\begin{array}{r}
Soda\ lime \\
(NaOH + CaO)
\end{array}}{\rightarrow}C_{6}H_{6} + CO_{2} \uparrow$
$\ \ \ \ \ \ \ \ \ \ (B)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.