(c)
According to Huckel’s rule an aromatic compound has $(4n + 2)\pi$-electrons, where, $n =$0, 1, 2, 3,…etc.
[image:13_image216.emf] ;$4n + 2 = 2;n = 0;aromatic$
[image:13_image217.emf]$;4n + 2 = 6;n = 1;aromatic$
[image:13_image218.emf] $;4n + 2 = 4;n = 0.5;non - aromatic$
[image:13_image219.emf] $;4n + 2 = 6;n = 1;aromatic$