Q. An alkene on vigorous oxidation with $KMnO_{4}$ gives only acetic acid. The alkene is
A) $CH_{3}CH_{2}CH = CH_{2}$
B) $CH_{3}CH = CHCH_{3}$
C) $\left( CH_{3} \right)_{2}C = CH_{2}$
D) $CH_{3}CH = CH_{2}$
Explanation
(b)
Since, the alkene of oxidation gives only acetic acid, therefore, the alkene must be symmetrical containing two carbon-atoms on either side of the double bond, $ie.,$ 2-butene.
$CH_{3}CH = CHCH_{3}\overset{{KMnO}_{4}}{\rightarrow}2CH_{3}COOH$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.