Q. $CH_{3} - CH_{2} - CH_{2} - CH_{3}\underset{HBr}{\overset{{AlCl}_{3}}{\rightarrow}}$ Product Product in the above reaction is
A) $CH_{3} - CH - CH_{2} - CH_{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Br$
B) $CH_{3} - CH - CH_{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |$
${\ \ \ \ \ \ \ \ \ \ \ \ \ CH}_{3}$
C) $CH_{3} - {CH}_{2} - CH_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ ||$
$\ \ \ \ \ \ \ \ \ \ \ BrBr$
D) All of these
Explanation
(b)
When alkene is passed over $AlCl_{3}$, isomerisation takes palce
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.