Q.
Select the reagent for the following reaction,
A) ${SeO}_{2}$
B) $O_{3},\ \frac{Zn}{H_{2}O}$
C) $O_{3},\ H_{2}O_{2} - {CH}_{3}COOH$
D) $PCC$
Explanation
(b)
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$Zn - H_{2}O$ is the reagent for reductive work up of ozonide. $H_{2}O_{2} - CH_{3}COOH$ would give $HOOC - \left( CH_{2} \right)_{4} - COOH$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.