Q. The reagent(s) for the following conversion, cis/are
A) Alcoholic $KOH$
B) Alcoholic $KOH$ followed by $NaNH_{2}$
C) Aqueous $KOH$ followed by $NaNH_{2}$
D) $\frac{Zn}{CH_{3}OH}$
Explanation
(c)
[image:13_image236.emf]
Vinylic bromide is more stable stronger base $( - NH_{2}^{-})$ is required for elimination.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.