Q. The major product P in the following reaction is $CH_{3} - CH = CH_{2}\underset{peroxide}{\overset{\ \ \ \ \ \ \ \ \ \ \ HI\ \ \ \ \ \ \ \ \ \ }{\rightarrow}}P$
A) $CH_{3}CH_{2}CH_{2}I$
B) $CH_{3} - CH - CH_{3}$
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$I$
C) $CH_{2} - CH = CH_{2}$
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$I$
D) $CH_{2} - CH_{2}$
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$I$ $I$
Explanation
(b)
The product of give reaction will be according to Markownikoff’s rule, this is because peroxide effect is applicable only in case of $HBr$ and not effective in case of $HI$.
$CH_{3} - CH = CH_{2}\underset{peroxide}{\overset{\ \ \ \ \ \ \ HI\ \ \ \ \ \ }{\rightarrow}}CH_{3} - CH - CH_{3}$
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$\ \ \ \ \ \ \ \ I$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.