Q. $CH_{3} - CH_{2} - C \equiv CH\underset{H_{2}SO_{4}}{\overset{\ \ HgSO_{4}\ \ \ \ }{\rightarrow}}A$ The compound A is
A) $O$
||
${CH}_{3} - {CH}_{2} - C - {CH}_{3}$
B) ${CH}_{3} - {CH}_{2} - {CH}_{2} - CHO$
C) ${CH}_{3} - {CH}_{2} - {CH}_{2} - COOH$
D) None of the above
Explanation
The correct answer is Option A: $O$ || ${CH}_{3} - {CH}_{2} - C - {CH}_{3}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.