Q. The treatment of $R^{'}MgX$ with $RC \equiv CH$ produces
A) $RH$
B) $R^{'}H$
C) $R - R$
D) $R - R^{'}$
Explanation
(b)
$R^{'}MgX + HC \equiv CR \rightarrow R^{'}H + RC \equiv CMgX$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.