Q. One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is
A) Propene
B) 1-butene
C) 2-butene
D) Ethene
Explanation
(c)
$C_{n}H_{2n}O = 44$
$C_{n}H_{2n} = 44 - 16 = 28$
$\therefore$ $n = 2$
So, $CH_{3} - CH = CH - CH_{3}$ is symmertrical alkene.
Thus,
$CH_{3} - CH = CH - CH_{3}\underset{II.Zn/H_{2}O}{\overset{\ \ \ \ \ \ \ I.O_{3}\ \ \ \ \ }{\rightarrow}}2CH_{3} - CH = O$
2-butene acetaldehyde
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.