(a)
$CH_{3} - C \equiv CH + HBr \rightarrow CH_{3} - C = CH_{2}$
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$Br$
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$CH_{3} - CH = CHBr\overset{HBr}{\rightarrow}CH_{3} - CH_{2} - CHBr_{2}$
$CH \equiv CH\overset{2HBr}{\rightarrow}CH_{3}{CHBr}_{2}$
$CH_{3} - CH = CH_{2}\overset{HBr}{\rightarrow}CH_{3} - CHBr - CH_{3}$