Q. In the following reaction, $C_{2}H_{2}\underset{HgSo_{4}/H_{2}SO_{4}}{\overset{{\ \ \ \ \ \ \ \ \ \ \ H}_{2}O\ \ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}X \rightleftharpoons CH_{3}CHO$ . What is X ?
A) ${CH}_{3}{CH}_{2}OH$
B) ${CH}_{3} - O - {CH}_{3}$
C) ${CH}_{3}{CH}_{2}CHO$
D) ${CH}_{2} = CHOH$
Explanation
The correct answer is Option D: ${CH}_{2} = CHOH$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.