Q. $CH_{3}C \equiv CH\underset{(2)\ CH_{3}CH_{2}Br}{\overset{(1){NaNH}_{2}}{\rightarrow}}A\underset{Lindlar^{'}s\ catalyst}{\overset{H_{2}}{\rightarrow}}B$ What is $B$ in the above reaction?

A) [image:13_image73.emf]
B) [image:13_image74.emf]
C) [image:13_image75.emf]
D) [image:13_image76.emf]
Explanation

The correct answer is Option B: [image:13_image74.emf].

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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