(d)
On ozonolysis,
$CH_{3}$
|
$CH_{2} = C = C - CH = CH_{2}$ gives two moles of $HCHO$, one mole of $CO_{2}$ one mole of $CH_{3}COCHO$.
$CH_{3}$
|
$CH_{2} = C = C - CH = CH_{2}\underset{Zn}{\overset{\frac{O_{3}}{H_{2}O}}{\rightarrow}}$
$2CH_{2}O + CO_{2} + CH_{3}COCHO$
(HCHO)