Q.
The product ‘X’ in the following reaction is
A) ${CH}_{3}Br - CH = {CH}_{2}$
B) $Br$
|
${CH}_{3} - C = {CH}_{2}$
C) ${CH}_{3}CH = CHBr$
D) None of the above
Explanation
(a)
[table] Column I | Column II ; Benzene | $(4n + 2)\pi$-electrons ; Ethylene | Mustard gas ; Acetaldehyde | Silver mirror ; Chloroform | Phosgene [/table]
Benzene has $6\pi$-electrons, $i.e.,$ it follows Huckel rule $(4n + 2)\pi$-electrons. Ethylene reacts with $S_{2}Cl_{2}$ to give mustard gas (war gas).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.