(a)
When propyne reacts with water in presence of $HgSO_{4}\ and\ H_{2}SO_{4}$ acetone is formed.
$CH_{3}C \equiv CH + H.OH\underset{H_{2}SO_{4}}{\overset{{Hg}^{2 +}}{\rightarrow}}CH_{3} - C = CH_{2}$
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$\ \ \ OH$
$\overset{\rightarrow}{Ketonisation}CH_{3} - C - CH_{2}$
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$O$