Q. A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is
A) 1,1-dibromopropane
B) 2,2-dibromopropane
C) 1,2-dibromoethane
D) 1,4-dibromobutane
Explanation
(d)
$\omega$ -dihalides when reacts with sodium metal, gives cyclic hydrocarbons. This is an example of intramolecular Wurtz reaction.
$CH_{2} - CH_{2}CH_{2} - CH_{2}\underset{- 2NaBr}{\overset{\ \ \ \ \ \ Na\ \ \ \ \ }{\rightarrow}}$
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$Br$ $Br$ cyclobutane
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.