Q. Ethylene reacts with 1% alkaline $KMnO_{4}$ to form
A) Oxalic acid
B) Ethylene glycol
C) Ethyl alcohol
D) $HCHO$
Explanation
(b)
Ethylene reacts with 1% alkaline $KMnO_{4}$ gives ethylene glycol.
$CH_{2}$ $CH_{2}OH$
$|| + H_{2}O + O\underset{KMnO_{4}}{\overset{1\%\ alkaline}{\rightarrow}}\ |\ \$
$CH_{2}$ $CH_{2}OH$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.