Q. Propylene on hydrolysis with sulphuric acid forms
A) $n$-propyl alcohol
B) Isopropyl alcohol
C) Ethyl alcohol
D) Butyl alcohol
Explanation
(b)
$OH$
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$CH_{2} = CH - CH_{3} + H_{2}O\overset{H_{2}{SO}_{4}}{\rightarrow}CH_{2} - CH - CH_{3}$
Propylene isopropyl alcohol
Thus, in this reaction isopropyl alcohol is formed.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.