Q. What are X and Y respectively, in the following reaction? $Z - product\overset{\ \ \ \ \ \ Y\ \ }{\leftarrow}2 - butyne\overset{\ \ \ X\ \ \ \ }{\rightarrow}E - product$
A) $\frac{Na}{{NH}_{3}(liq.)}\ and\ \frac{Pd}{{BaSO}_{4}} + H_{2}$
B) $\frac{Ni}{140℃}\ and\ \frac{Pd}{{BaSO}_{4}} + H_{2}$
C) $\frac{Ni}{140℃}\ and\ \frac{Na}{{NH}_{3}(liq.)}$
D) $\frac{Pd}{{BaSO}_{4} + H_{2}}\ and\ \frac{Na}{{NH}_{3}(liq.)}$
Explanation
(a)
[image:13_image293.emf]
Hence, reagent X and Y are respectively $Na,NH_{3}\ and\ \frac{Pd}{BaSO_{4} + H_{2}}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.