Q. $A\left( C_{4}H_{6} \right)\underset{1\ mole}{\overset{H_{2},\ Ni\ \ \ }{\rightarrow}}B\left( C_{4}H_{8} \right)\overset{O_{3}/H_{2}O/Zn}{\rightarrow}CH_{3}CHO$ Thus, $A$ and $B$ are
A) [image:13_image171.emf]
B) [image:13_image172.emf]
C) $CH_{3}CH_{2}C \equiv CH,\ CH_{3}CH = CHCH_{3}$
D) $CH_{2} = CH - CH = CH_{2},\ CH_{3}CH = CH - CH_{3}$
Explanation
The correct answer is Option D: $CH_{2} = CH - CH = CH_{2},\ CH_{3}CH = CH - CH_{3}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.