Q. Acetylene can be obtained by the reaction?
A) $HCOOK\overset{Electrolysis\ \ \ \ }{\rightarrow}$
B) $CHI_{3} + Ag\overset{\ \ \ \ \ \mathrm{\Delta}\ \ \ \ \ }{\rightarrow}$
C) $CH_{3}{CH}_{2}OH\underset{443\ K}{\overset{Conc.H_{2}SO_{4}\ \ }{\rightarrow}}$
D) ${Be}_{2}C + H_{2}O \rightarrow$
Explanation
(b)
Iodoform and Ag undergo dehalogenation reaction to produce acetylene.
(A)$HCOOK + H_{2}O\overset{\mathrm{\Delta}}{\rightarrow}H_{2} + {CO}_{2} + KOH$
(B)$2CHI_{3} + 6Ag\overset{\mathrm{\Delta}}{\rightarrow}CH \equiv CH + 6AgI$
Iodoform silver acetylene
(C)$CH_{3}{CH}_{2}OH\underset{443K}{\overset{Conc.H_{2}SO_{4}\ \ }{\rightarrow}}CH_{2} = CH_{2} + H_{2}O$
Ethylene
(D)${Be}_{2}C + H_{2}O \rightarrow {CH}_{4}$
methane
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.