Q. $Ph - C \equiv C - CH_{3}\overset{\frac{Hg^{2 +}}{H^{+}}}{\rightarrow}A$ The product A is
A) [image:13_image183.emf]
B) [image:13_image184.emf]
C) [image:13_image185.emf]
D) [image:13_image186.emf]
Explanation
(a)
$Ph - C \equiv C - CH_{3}\overset{\frac{Hg^{2 +}}{H^{+}}}{\rightarrow}Ph - C = CH - CH_{3}$
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$OH$
$Ph - C = {CH}_{2}CH_{3}$
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$O$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (A)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.