Q. Which of the following will have a $meso$-isomer also?

A) 2-chlorobutane
B) 2, 3-dichlorobutane
C) 2, 3-dichloropentane
D) 2-hydroxypropanoic acid
Explanation

(b)
(A)$CH_{3} - CH - CH_{2}CH_{3}$
|
Cl
One asymmetric carbon atom, forms$\ d$, and $l -$optical and isomers.
(b) Two asymmetric carbon atoms, forms $d$, $l$ and $meso$ forms
[image:12_image291.emf]
$Meso$ due to internal compensation
[image:12_image292.emf]
Two asymmetric carbon atoms but does not have symmetry. Hence, $meso$ form is not formed.
[image:12_image293.emf]
One asymmetric carbon atom, $meso$ form is not formed.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.