Q. The compound in which carbon uses only its $sp^{3}$ hybrid orbitals for bond formation is
A) $\left( CH_{3} \right)_{3}COH$
B) $HCOOH$
C) $CH_{3}CHO$
D) $\left( H_{2}N \right)_{2}CO$
Explanation
(a)
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All bonds are $\sigma$- bonds hence C uses only its $sp^{3}$-hybrid orbitals. In all other compounds there is one $C = O$ double bond, therefore, this carbon is $sp^{2}$- hybridized
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.