Q. In Kjeldahl’s method, ammonia from 5g of food neutralizes 30 $cm^{3}$ of 0.1 N acid. The percentage of nitrogen in the food is
A) 0.84
B) 8.4
C) 16.8
D) 1.68
Explanation
(a)
From Kjeldahl’s method,
Percentage of nitrogen
$= \frac{1.4 \times N \times V}{W} = \frac{1.4 \times 0.1 \times 30}{5}$
$= 0.84\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.