Q. Which of the following orders regarding relative stability of free radicals is correct?

A) 3${^\circ}$<2${^\circ}$<1${^\circ}$
B) 3${^\circ}$>2${^\circ}$>1${^\circ}$
C) 1${^\circ}$<2${^\circ}$>3${^\circ}$
D) 3${^\circ}$>2${^\circ}$<1${^\circ}$
Explanation

(b)
Free radicals are electrons deficient compounds. Alkyl groups are electron donor groups and they increase the stability of free radicals.
∴ More the number of alkyl groups, more will be stability of free radicals.
∴ 3${^\circ}$>2${^\circ}$>1${^\circ}$ is the correct order of stability of free radicals.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.