Q. Which one of the following will show optical isomerism?
A) $\ \ \ \ \ \ \ \ \ \ \ \ H$
|
$HO - C - CO_{2}H$
|
H
B) H
|
$H_{3}C - C - CO_{2}H$
|
OH
C) $\ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
|
$H_{3}C - C - CO_{2}H$
|
H
D) $\ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
|
$H_{3}C - C - CO_{2}H$
|
Cl
Explanation
(b)
The central carbon is attached to four different substituents, hence it is chiral, therefore optically active.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.