(a) Angle strain, $\alpha = \frac{1}{2}\left\lbrack 109{^\circ}28^{'} - \theta \right\rbrack$ In case of cyclopropane, $\theta = 60{^\circ}$ $\therefore\alpha = \frac{1}{2}\left( 109{^\circ}28^{'} - 60{^\circ} \right) = 24{^\circ}44'$
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