Q. In estimation of nitrogen by Duma's method 1.18 g of an orgainc compound gave 224 mL of $N_{2}$ at NTP. The percentage of nitrogen in the compound is
A) 20.0
B) 11.8
C) 47.7
D) 23.7
Explanation
(d)
$\%\ of\ N\frac{28}{22400} \times \frac{volume\ of\ N_{2}at\ NTP}{wt.of\ compound} \times 100$
$= \frac{28}{22400} \times \frac{224}{1.18} \times 100$
$= \frac{28}{1.18} = 23.728$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.