Q. $t$-butyl chloride reacts with $OH^{-}$ by $S_{N}1$ mechanism and rate $\propto \lbrack t$-buty1 chloride]. One of the reasons for this is that
A) Stereochemical inversion takes place
B) $t$- buty1 carbocation is first formed which is more stable
C) The product $t$-butyl alcohol is more stable
D) The intermediate $t$-butyl carbocation is stabilized by solvation
Explanation
(b)
$\ \ CH_{3}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
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$CH_{3} - C - Cl + OH^{-}\ \rightarrow HO - C - CH_{3} + Cl^{-}$
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$CH_{3}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
Rate $\propto \lbrack t$-butyl chloride]
Tertiary butyl carbocation is first formed which is more stable
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.