(c) $\%\ of\ H = \frac{2}{18} \times \frac{weight\ of\ H_{2}O}{weight\ of\ organic\ compound\ } \times 100$ $= \frac{2}{18} \times \frac{0.9}{0.5} \times 100 = 20\%$ $\therefore$ The percentage of carbon $= 100 - 20 = 80\ \%$
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Ph.D. in Physics with 19+ years of teaching experience.