Q. 0.25 g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise 10$cm^{3}$ of 0.5M $H_{2}SO_{4}$. The percentage of nitrogen in the compound is
A) 28
B) 56
C) 14
D) 112
Explanation
(b)
From kjeldahl’s method,
Percent of nitrogen $= \frac{1.4 \times N \times V}{W}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1.4 \times 0.5 \times 2 \times 10}{0.25} = 56\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.